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| herabrienna
# Statistics
Favourites: 1319; Deviations: 34; Watchers: 46
Watching: 39; Pageviews: 4026; Comments Made: 53; Friends: 39
# About me
Hi! Δ°'m Herabrienna!-I'm Turkish
-I'm Daughter of Herobrine in my dream :3
-I'm a demigod :3 (Poseidon)
-I'm 16 years old
# Comments
Comments: 55
JewelLianAlexandrias [2022-02-27 04:11:52 +0000 UTC]
π: 0 β©: 0
Bleeding-Aquarius [2019-07-11 07:23:17 +0000 UTC]
"Didn't know I had a daughter!"Β Β Β Β (Thanks for the favourite!)
π: 0 β©: 1
Bleeding-Aquarius In reply to Bleeding-Aquarius [2019-07-11 08:54:34 +0000 UTC]
Β "I think she's cute, congratulations!"Β Β
π: 0 β©: 1
Bleeding-Aquarius In reply to Bleeding-Aquarius [2019-07-11 09:10:16 +0000 UTC]
π: 0 β©: 0
herabrienna In reply to CarrotParrotDraws [2019-05-16 16:08:43 +0000 UTC]
Ben herkesi bulurum sjsjsbsnnsjjj
π: 0 β©: 1
CarrotParrotDraws In reply to herabrienna [2019-05-16 19:02:39 +0000 UTC]
Ya beni niye instagramdan engelledin adΔ±m _carrotparrotdraws_ ne yaptim ben sana :' <
π: 0 β©: 0
herabrienna In reply to Cundyyuuu [2019-05-16 16:09:06 +0000 UTC]
Bende seniΔΔΔΔ *-*
π: 0 β©: 0
VittoriaCraft [2018-08-26 18:59:58 +0000 UTC]
Hello! I found your profile interesting. I found your marvelous arts and thank you for the favorite of that drawing of the "New Oc of the Herobrine".
π: 0 β©: 0
RANIAbs [2017-09-02 21:24:36 +0000 UTC]
Thanks for the fave on ask hero. If you want to ask a quest then welcom.
π: 0 β©: 0
Flame-Bloom [2017-08-27 09:04:43 +0000 UTC]
Thank you for the favourites! Feel free to ask all the questions you want in the ask blog! ^_^
π: 0 β©: 0
DigitalSpiritWolf [2017-07-04 21:12:41 +0000 UTC]
Thanks for the fav but oh god why I need to redraw that one XD
π: 0 β©: 0
MCStevebrine12 [2017-03-27 12:18:18 +0000 UTC]
erm... on your profile it says that you are male.... but you say you are Herobrine's Daughter....
wut???
π: 0 β©: 1
hesterfunhart In reply to MCStevebrine12 [2017-06-21 15:21:32 +0000 UTC]
She already fixed it ^^
π: 0 β©: 1
MCStevebrine12 In reply to hesterfunhart [2017-06-21 15:27:21 +0000 UTC]
π: 0 β©: 1
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