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DorottyaS — Learn how to love - Heart 24

Published: 2012-12-01 12:10:17 +0000 UTC; Views: 15584; Favourites: 1536; Downloads: 0
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Description Heart 24
Learn how to love

Analysis can be inspiring sometimes Or maybe I'm just getting crazy because I learn too much math nowadays and I worry too much about the exams. But I really want to do it as good as I can.

I know, I don't have much time for this project but I don't want to finish it with boring pictures. This project made me totally fall in love with conceptual photography and I want to make more interesting heart pictures. So I hope you don't mind if I won't upload heart photos too often.

We can only learn to love by loving.
- Iris Murdoch

(It's also part of my Study Series 04)

Texture: sirius-sdz.deviantart.com/art/…

Featured:
fav.me/d5n5s0x
fav.me/d5qlmi6
fav.me/d72n8tw
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Comments: 154

DorottyaS In reply to ??? [2013-03-04 07:47:18 +0000 UTC]

thank you

👍: 0 ⏩: 0

Serpent-Power [2012-12-19 18:18:11 +0000 UTC]

Flagged as Spam

👍: 0 ⏩: 1

DorottyaS In reply to Serpent-Power [2012-12-20 22:26:44 +0000 UTC]

thanks

👍: 0 ⏩: 0

AraniaEqualor [2012-12-04 23:05:07 +0000 UTC]

u r featured here: [link]

👍: 0 ⏩: 1

DorottyaS In reply to AraniaEqualor [2012-12-15 14:31:05 +0000 UTC]

thank you so much

👍: 0 ⏩: 1

AraniaEqualor In reply to DorottyaS [2012-12-16 01:05:16 +0000 UTC]

uh huh

👍: 0 ⏩: 0

moonlightwalk [2012-12-04 18:11:41 +0000 UTC]

Nah, far more beautiful than the graphs I have been studying all day ^^

👍: 0 ⏩: 1

DorottyaS In reply to moonlightwalk [2012-12-15 14:30:54 +0000 UTC]

thank you

👍: 0 ⏩: 0

lajvio [2012-12-02 16:24:09 +0000 UTC]

I wish I could learnt this equation as well...
beautiful picture.

👍: 0 ⏩: 1

DorottyaS In reply to lajvio [2012-12-15 14:30:42 +0000 UTC]

thank you
I made this after this picture: [link]

👍: 0 ⏩: 0

BellaGBear [2012-12-02 11:23:17 +0000 UTC]

haha this one is really awesome. I get the feeling of too much math when I was still at high-school

👍: 0 ⏩: 1

DorottyaS In reply to BellaGBear [2012-12-15 14:30:08 +0000 UTC]

thank you

👍: 0 ⏩: 0

Nenril-Tf [2012-12-02 11:14:27 +0000 UTC]

It's a Cardioide! p(o)=1-cos(o)!

👍: 0 ⏩: 1

DorottyaS In reply to Nenril-Tf [2012-12-15 14:29:57 +0000 UTC]

👍: 0 ⏩: 0

Angel-Moose [2012-12-02 10:08:46 +0000 UTC]

wonderful idea...

👍: 0 ⏩: 1

DorottyaS In reply to Angel-Moose [2012-12-15 14:29:50 +0000 UTC]

thanks

👍: 0 ⏩: 0

DeadWaste2 [2012-12-02 09:46:38 +0000 UTC]

[link] ^0.01%2C+-sqrt%289-x^2%29+from+-4.5+to+4.5


here is the function to this heart

👍: 0 ⏩: 1

DorottyaS In reply to DeadWaste2 [2012-12-15 14:29:44 +0000 UTC]

thanks for sharing

👍: 0 ⏩: 1

DeadWaste2 In reply to DorottyaS [2012-12-23 11:17:31 +0000 UTC]

more like this, sorry

[link]

👍: 0 ⏩: 0

waterwings19 [2012-12-02 08:27:46 +0000 UTC]

This is so beautiful, I swear!

👍: 0 ⏩: 1

DorottyaS In reply to waterwings19 [2012-12-15 14:29:32 +0000 UTC]

thank you

👍: 0 ⏩: 0

SammySideUp00 [2012-12-02 08:16:05 +0000 UTC]

Really cute!:]

👍: 0 ⏩: 1

DorottyaS In reply to SammySideUp00 [2012-12-15 14:29:23 +0000 UTC]

thanks

👍: 0 ⏩: 1

SammySideUp00 In reply to DorottyaS [2012-12-27 12:19:49 +0000 UTC]

No prob

👍: 0 ⏩: 0

Magunick [2012-12-02 04:52:51 +0000 UTC]

XD I did that once, too much math~ I did it without thinking

👍: 0 ⏩: 1

DorottyaS In reply to Magunick [2012-12-15 14:29:16 +0000 UTC]

👍: 0 ⏩: 0

Phoenixfur [2012-12-02 04:50:17 +0000 UTC]

Just for anyone wanting to know, you can graph it in a graphing calculator by putting in:
y1=abs value of (x) + [sqrt of (1-x^2)] and y2=abs value of (x) - [sqrt of (1-x^2)]
then set your window to all 2's or -2's

👍: 0 ⏩: 1

DorottyaS In reply to Phoenixfur [2012-12-15 14:29:07 +0000 UTC]

thanks for sharing

👍: 0 ⏩: 0

KleioAmon [2012-12-02 03:45:49 +0000 UTC]

beautiful

👍: 0 ⏩: 1

DorottyaS In reply to KleioAmon [2012-12-15 14:28:12 +0000 UTC]

thanks

👍: 0 ⏩: 0

Jousan [2012-12-02 03:41:40 +0000 UTC]

beautiful <3

👍: 0 ⏩: 1

DorottyaS In reply to Jousan [2012-12-15 14:28:04 +0000 UTC]

thanks

👍: 0 ⏩: 0

SakooriUxiegirl44 [2012-12-02 03:10:32 +0000 UTC]

I don't remember the formula to do that.

There is actually a legit formula and I forget it.

👍: 0 ⏩: 3

DorottyaS In reply to SakooriUxiegirl44 [2012-12-15 14:27:49 +0000 UTC]

I used this one: [link]

👍: 0 ⏩: 0

Phoenixfur In reply to SakooriUxiegirl44 [2012-12-02 04:51:39 +0000 UTC]

y1=abs value of (x) + [sqrt of (1-x^2)] and y2=abs value of (x) - [sqrt of (1-x^2)]
then set your window to all 2's or -2's

👍: 0 ⏩: 0

Fangscream In reply to SakooriUxiegirl44 [2012-12-02 04:35:06 +0000 UTC]

Same, lol! I remember glimpsing at it in my trig book. I'm sure you can look it up somewhere.

👍: 0 ⏩: 0

razzlepazzledoodot [2012-12-02 02:51:52 +0000 UTC]

If only math were as fun as drawing great pic, very creative

👍: 0 ⏩: 1

DorottyaS In reply to razzlepazzledoodot [2012-12-15 14:27:31 +0000 UTC]

thank you

👍: 0 ⏩: 1

razzlepazzledoodot In reply to DorottyaS [2012-12-18 03:04:55 +0000 UTC]

welcome

👍: 0 ⏩: 0

compoundsomenouns [2012-12-02 02:42:38 +0000 UTC]

r=1-sin(theta)!

👍: 0 ⏩: 1

DorottyaS In reply to compoundsomenouns [2012-12-15 14:27:15 +0000 UTC]

I used this one: [link]

👍: 0 ⏩: 0

ProFingerboarder [2012-12-02 02:36:31 +0000 UTC]

I always use the graph paper from math class to play Dungeons and Dragons on lol

👍: 0 ⏩: 1

DorottyaS In reply to ProFingerboarder [2012-12-15 14:27:04 +0000 UTC]

👍: 0 ⏩: 0

qqannie [2012-12-02 00:28:59 +0000 UTC]

This is very pretty.

👍: 0 ⏩: 1

DorottyaS In reply to qqannie [2012-12-15 14:26:56 +0000 UTC]

thanks

👍: 0 ⏩: 0

WheresYour-HeART [2012-12-01 23:21:09 +0000 UTC]

Very beautiful!! And you have chosen the perfect quote with your deviation. Love it!!

👍: 0 ⏩: 1

DorottyaS In reply to WheresYour-HeART [2012-12-15 14:26:48 +0000 UTC]

thank you

👍: 0 ⏩: 1

WheresYour-HeART In reply to DorottyaS [2012-12-15 14:43:27 +0000 UTC]

You're very welcome

👍: 0 ⏩: 0

Lonacc [2012-12-01 23:04:15 +0000 UTC]

trust me, I'm an engineer.

👍: 0 ⏩: 1

DorottyaS In reply to Lonacc [2012-12-15 14:26:24 +0000 UTC]

👍: 0 ⏩: 0


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