Comments: 31
TheXboxOneFan [2015-06-26 19:27:21 +0000 UTC]
Ruben looks so fancy!
π: 0 β©: 1
TonyYorkieSilky1991 In reply to Wolfmage90 [2015-06-24 00:41:49 +0000 UTC]
I like his pose and the way he's dressed. It makes him cool and sophisticated.
π: 0 β©: 1
Wolfmage90 In reply to TonyYorkieSilky1991 [2015-06-24 00:43:09 +0000 UTC]
Have YOU ever dressed in an outfit like that before, or even considered trying?
Thanks, btw
π: 0 β©: 1
TonyYorkieSilky1991 In reply to Wolfmage90 [2015-06-24 00:44:43 +0000 UTC]
I have been dressed like that, but only at fancy places. You're welcome, btw.
π: 0 β©: 1
TonyYorkieSilky1991 In reply to Wolfmage90 [2015-06-24 00:51:41 +0000 UTC]
And speaking of dressing fancy, have you dressed like Ruben before?
π: 0 β©: 1
Wolfmage90 In reply to TonyYorkieSilky1991 [2015-06-24 00:53:22 +0000 UTC]
No, but I certainly wouldn'tΒ mind it. Ruben isn't a Mary Sue by the way, he's just a dapper dog.
π: 0 β©: 1
TonyYorkieSilky1991 In reply to Wolfmage90 [2015-06-24 00:58:06 +0000 UTC]
You mean Gary Stu. And I know that Ruben is no Mary Sue. He's my second favorite of the Gomes brothers.
π: 0 β©: 1
KBAFourthtime [2015-06-24 00:24:24 +0000 UTC]
Great work.
π: 0 β©: 1
Wolfmage90 In reply to KBAFourthtime [2015-06-24 00:28:50 +0000 UTC]
You should also thank Calamity Coyote,Β or Chris Vanderford,Β he helped design Ruben into what he is today.
π: 0 β©: 1
Wolfmage90 In reply to KBAFourthtime [2015-06-24 00:37:00 +0000 UTC]
They're both the same person! Calamity Kangaroo is Chris Vanderford's DA name as well as the main character in his series Outback.
π: 0 β©: 1
KBAFourthtime In reply to Wolfmage90 [2015-06-24 00:37:39 +0000 UTC]
I know, but let me guess the icon:
π: 0 β©: 1
KBAFourthtime In reply to Wolfmage90 [2015-06-24 00:39:19 +0000 UTC]
I know no other Calamity Coyote user.
π: 0 β©: 1
Wolfmage90 In reply to KBAFourthtime [2015-06-24 00:42:31 +0000 UTC]
It's Calamity Kangaroo, not Calamity Coyote!
π: 0 β©: 1
Wolfmage90 In reply to KBAFourthtime [2015-06-24 00:58:24 +0000 UTC]
Good, that was the right thing to do
π: 0 β©: 0