Comments: 56
Ratwo619 [2015-04-23 01:19:33 +0000 UTC]
This is soooo Thomas Sanders!!
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burntuakrisp [2015-03-29 21:18:12 +0000 UTC]
Maybe I could solve it
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livesfordrawings [2015-03-28 12:23:55 +0000 UTC]
Does this happen in every class XD
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Ismalith [2015-03-24 22:52:49 +0000 UTC]
Why did you use two variables?
1122x²+4257yx+2x-4y
-----------------------------
x² +393xy + 390y²
Is as far as I can go here, fore more there is only plotting in math programs as far as my abilities go.
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andrz00 [2015-03-24 01:22:21 +0000 UTC]
¿Porque lo golpeaste?
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tigreanpony [2015-03-23 20:57:31 +0000 UTC]
Lol, that was hilarious. but in the second that question still stands true. Truth be told that type of math is more for technical work and scientific work but still is funny.
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sweetymimy22 [2015-03-23 17:20:02 +0000 UTC]
hahaha no really why should we know that ....?? Such computing tasks take more than the scientists
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Deviantaphant [2015-03-23 03:42:53 +0000 UTC]
The furthest I could get was 2x(561x+1)+y(4257-4)
___________________
(390y^2)+3xy+x
Is that good enough, Twilight?
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Azzzanadra In reply to PaulySentry [2015-03-23 19:31:44 +0000 UTC]
no, he needs to find the value of x and y.
i don't think that's how you do it either.
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PaulySentry In reply to Azzzanadra [2015-03-23 21:13:15 +0000 UTC]
I suck at algebra. So, I technically don't know what did he do.
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PaulySentry In reply to Extraxi [2015-03-23 06:35:45 +0000 UTC]
Hehe, have you watched it? It's pretty good. Thanks!
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Extraxi In reply to PaulySentry [2015-03-23 22:20:40 +0000 UTC]
I have seen a version of it, I don't know if it's the original.
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TheAdorableOshawott [2015-03-22 23:38:08 +0000 UTC]
Y apenas estoy viendo el método de factorización. :v
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TheAdorableOshawott In reply to PaulySentry [2015-03-23 00:26:58 +0000 UTC]
Eso ya lo vi el año pasado, no está tan difícil si pones atención. :v
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Fee-F33 [2015-03-22 23:31:19 +0000 UTC]
I say that all the time
for new problems, then I see why ^^'
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PaulySentry In reply to Fee-F33 [2015-03-22 23:34:40 +0000 UTC]
XD Yeah, you'll never know when something like this could happen.
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Hero-Mode [2015-03-22 22:21:49 +0000 UTC]
But I suck at math, always have.
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PaulySentry In reply to Hero-Mode [2015-03-22 22:24:01 +0000 UTC]
I don't suck at math, I just don't like it.
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Count-Author [2015-03-22 22:10:53 +0000 UTC]
AHAHAHAHAHAH!!! NOBODY SAID THERE'D BE MATH!!!
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Count-Author In reply to PaulySentry [2015-03-22 22:22:09 +0000 UTC]
Eeyup! Too bad you flunked that math course!
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liamwhite1 [2015-03-22 21:54:15 +0000 UTC]
Solve for x:
x(x - 2 + m²x + 2mb + 2mk) = r² - b² - h² + 2bk
Have fun.
(PROTIP: don't try, moron)
👍: 0 ⏩: 2
liamwhite1 In reply to Crad-Rin-Vah [2015-03-22 22:31:35 +0000 UTC]
x(x - 2 + m²x + 2mb + 2mk) = r² - b² - h² + 2bk
rewrite as quadratic
x(x + m²x + 2mb + 2mk) - 2x = r² - b² - h² + 2bk
x²(1 + m²) + x(2mb + 2mk - 2) = r² - b² - h² + 2bk
complete the square
x² + x(2mb + 2mk - 2)/(1 + m²) = (r² - b² - h² + 2bk) / (1 + m²)
x² + x(2mb + 2mk - 2)/(1 + m²) + (2mb + 2mk - 2)²/(2 + 2m²)² = (r² - b² - h² + 2bk) / (1 + m²) + (2mb + 2mk - 2)²/(2 + 2m²)²
(x + (2mb + 2mk - 2)/(2 + 2m²))² = (r² - b² - h² + 2bk) / (1 + m²) + (2mb + 2mk - 2)²/(2 + 2m²)²
isolate
x + (2mb + 2mk - 2)/(2 + 2m²) = ± √(r² - b² - h² + 2bk) / (1 + m²) + (2mb + 2mk - 2)²/(2 + 2m²)²
x = - (2mb + 2mk - 2)/(2 + 2m²) ± √((r² - b² - h² + 2bk) / (1 + m²) + (2mb + 2mk - 2)²/(2 + 2m²)²)
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plushbrony101 [2015-03-22 21:49:20 +0000 UTC]
my worst nightmare
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